Answer:
Recall the Diffraction grating formula for constructive interference of a light
y = nDλ/w Eqn 1
Where;
w = width of slit = 1/15000in =6.67x10⁻⁵in =
6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m
D = distance to screen
λ = wavelength of light
n = order number = 1
Given
y1 = ? from 1st order max to the central
D = 2.66 m
λ = 633 x 10-9 m
and n = 1
y₁ = 0.994m
Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 1) = 0.994m
Q b. How far (m) from the central maximum (m = 0) is the second-order maximum (m = 2) observed?
w = width of slit = 1/15000in =6.67x10⁻⁵in =
6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m
D = distance to screen
λ = wavelength of light
n = order number = 1
Given
y1 = ? from 1st order max to the central
D = 2.66 m
λ = 633 x 10⁻⁹ m
and n = 2
y₂ = 0.994m
Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 2) =1.99m
Answer:
A, I think its A but im not sure.
Explanation:
Answer:
101.19keV
Explanation:
r1 = 1.0cm = 0.01m
r2 = 1.90cm = 0.019m
B = 0.050T
q = 1.60*10^-19C
m = 9.11 * 10^-31 kg
Mv /r = qB
v = rqB / m
v1 = (0.01 * 1.60*10^-19 * 0.05) / 9.11 * 10^-31
v1 = 8.78 * 10⁷ m/s
V2 = (0.019 * 1.60*10^-19 * 0.05) / 9.11 * 10^-31
V2 = 1.67 * 10⁸ m/s
Kinetic energy of the system K.E = K.E₁ + K.E₂
K.E₁ = ½mv₁² = ½ * 9.11 *10⁻³¹ * (8.78*10⁷)²
k.e₁ = 3.511 * 10⁻¹⁵ J
k.e₂ = 1/2 mv₂² = 1/2 * 9.11*10⁻³¹ * (1.67*10⁸)²
k.e₂ = 1.27*10⁻¹⁴J
K.E = k.e₁ + k.e₂
K.E = 3.511*10⁻¹⁵ + 1.27*10⁻¹⁴
K.E = 1.6211*10⁻¹⁴J
1eV = 1.602 * 10⁻¹⁹J
xeV = 1.6211*10⁻¹⁴J
x = 101,192.23eV = 101.192keV
1. Record the barometric pressure.<span> </span>2. Measure about 10 g of ice using the chemical balance and place it into a 100 mL beaker.<span> </span>
Answer:
what is speed
how to tell what speed an objeckt is moveing
vlocity
Explanation: