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neonofarm [45]
3 years ago
13

We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5.7

g.
a. Find the number of atoms in a nickel coin. Each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g. Answer in units of atoms.
b. Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons.
c. Find the magnitude of the charge of all these electrons. Answer in units of C.
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0
<span>5.6x10e22 atoms
Hope I helped, and good luck!

</span>
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Neon has 10 protons and 10 electrons. How many additional electrons would it take to fill the outer (second) electron shell?
blondinia [14]
The first shell has 2 in and the second shell has 8 in therefore ypuvwont need to add anymore :-) so the answer is 0
6 0
3 years ago
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A proton is launched from an infinite plane of charge with surface charge density -1.10×10-6 C/m2. If the proton has an initial
Katyanochek1 [597]

The distance covered by the proton is 48.4 m

Explanation:

The electric field produced by an electrically charged infinite plane is given by

E=\frac{\sigma}{2\epsilon_0}

where in this case,

\sigma = -1.10\cdot 10^{-6} C/m^2 is the surface charge density

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

Substituting,

E=\frac{-1.10\cdot 10^{-6}}{2(8.85\cdot 10^{-12})}=-5.65\cdot 10^4N/C

And the direction is towards the plane (because the charge is negative).

The electric force on the proton due to this field is

F=qE

where

q=1.6\cdot 10^{-19}C is the proton charge

Substituting,

F=(1.6\cdot 10^{-19})(-5.65\cdot 10^4)=-9.0\cdot 10^{-15} N

where the direction is toward the plane.

Now we can calculate the proton's acceleration using Newton's second law:

a=\frac{F}{m}

where

m=1.67\cdot 10^{-27}kg is the proton mass

Substituting,

a=\frac{-9.0\cdot 10^{-15}}{1.67\cdot 10^{-27}}=-5.4\cdot 10^{-12} m/s^2

Now we can finally apply the following suvat equation for accelerated motion to find the distance travelled by the proton:

v^2-u^2=2as

where

v = 0 is the final velocity

u=2.40\cdot 10^7 m/s is the initial velocity

a is the acceleration

s is the distance covered

And solving for s,

s=\frac{v^2-u^2}{2a}=\frac{0-(2.4\cdot 10^7)^2}{2(-5.4\cdot 10^{12})}=53.3 m

Therefore, the closest answer is 48.4 m.

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.
andreev551 [17]

Answer:

1.904

Explanation:

F= ma

8 = 4.2 a

a = 8/4.2

a = 1.904

6 0
2 years ago
Một dây dẫn bằng nikelin có điện trở suất là ρ = 0,4.10-6 Ωm, dài l = 5m, tiết diện
MAXImum [283]

Answer:

Một dây dẫn bằng nikelin dài 20m, tiết diện 0.5mm2 điện trở suất của nikelin là 0,4.10^-6 ôm/m. tính điện trở dây dẫn

6 0
3 years ago
If the core of jupiter is 30,000 celcius and it is five times hotter than the sun, what's the temperature of the surface of the
VMariaS [17]
Let, the temperature of Sun's surface = c

So, 5c = 30, 000
c = 30,000 / 5
c = 6,000

In short, Your Answer would be 6000

Hope this helps!
6 0
4 years ago
Read 2 more answers
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