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2 years ago

If 0.5% of a number is 250, find the number

Mathematics

2 answers:

kaheart [24]2 years ago

6 0

0.5% or 1/2% of say "x" is 250, whilst "x" is the 100%.

$\begin{array}{ccll} \%&amount\\ \cline{1-2} \frac{1}{2}&250\\[1em] 100&x \end{array}\implies \cfrac{~~ \frac{1}{2}~~}{100}=\cfrac{250}{x}\implies \cfrac{1}{200}=\cfrac{250}{x}\implies x = 50000$

Volgvan2 years ago

3 0

Answer:

1.25

Step-by-step explanation:

Convert that percentage to either fraction or decimal:

0.5

0.005

2) Simply multiply your result by the total number

which in this case is 250:

0.005

250

1.25

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Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

2 years ago

Khalid carried water bottles to the field to share with his team at halftime. The water bottles weighed

jeka57 [31]

Answer:

<u>Answer</u><u>:</u><u> </u><u>D</u>

${50x}^{2} + 30x + 10$

• first factorise out 10:

$= 10(5 {x}^{2} + 3x + 1)$

• then find factors of the quadratic equation in the bracket:

4 0

3 years ago

How can I work out 30% of (blank) is 60?

geniusboy [140]

60/ (30/100)
= 60* (100/30)
= 200

The final answer is 200~

3 0

3 years ago

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A painting measures b meters by 4 meters. a frame shop charges $10 per meter for a wooden frame. how much would it cost to buy a

hammer [34]

$ (20b + 80) is the cost to buy a frame for the panting given that measures b meters by 4 meters and charges $10 per meter for a wooden frame. This can be obtained by finding the perimeter of the painting and multiplying with the cost of wood per meter.

<h3>What is the cost of buying a frame for the painting?</h3>

Given that,

length of the painting (l) = b meters

width of the painting (b) = 4 meters

Perimeter of the painting = 2(l+b)

= 2(b+4)

= 2b + 8

Cost of the frame = (2b + 8)× $10 per meter

= $ (20b + 80)

Hence $ (20b + 80) is the cost to buy a frame for the panting given that measures b meters by 4 meters and charges $10 per meter for a wooden frame.

Learn more about finding cost of frame:

brainly.com/question/16757070

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2 years ago

Mindy buys 12 cupcakes. Nine of the cupcakes have chocolate frosting. What fraction of the cupcakes have vanilla frosting?

Mrac [35]

1 fourth which as a fraction would look like:

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