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2 years ago

How do i find the nth sequence in this sequen 7cm 10cm 13cm 16cm

Mathematics

2 answers:

Butoxors [25]2 years ago

4 0

Answer:

$a_{n}$ = 3n + 4

Step-by-step explanation:

There is a common difference between consecutive terms in the sequence

10 - 7 = 13 - 10 = 16 - 13 = 3

This indicates the sequence is arithmetic with nth term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 3 , then

$a_{n}$ = 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4

german2 years ago

3 0

Answer:

This is a sequence of 3 added to digits which start from 7 so 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49, 52, 55, 58, 61, 64, 67, 70, etc.

If u wanna find the 9th sequence the answer is 31

Step-by-step explanation:

Hope it helps :D

Brainliest?

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a doctors office surveyed their patients on wait time satisfaction, with a scale of 1bto 5. The data listed below are the report

liubo4ka [24]

Answer:

See Attached

Step-by-step explanation:

The survey on wait time satisfaction for patients at a doctor's office generated the reported scores below.

1,3,2,3,3,4,4,1,5,3,3,3,4,4,5,2,2,2,1,1

First we sort making sure the total number of scores equal 20:

1,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,5,5

Frequency of 1=4
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Next, we draw the dot plot which is attached below.

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3 years ago

The volume of a triangular prism is increased by a factor of 8.

Nuetrik [128]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Anyone know this answer I will give you 28 point.

maks197457 [2]

Answer:

V to X = 68mi

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Step-by-step explanation:

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2 years ago

A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts

Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

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2 years ago

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alexandr402 [8]

We use ratio and proportion to solve each of these:

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