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Oksana_A [137]
3 years ago
11

Please answer this correctly without making mistakes

Mathematics
2 answers:
Katena32 [7]3 years ago
4 0

ANSWER :

<u>Percentage = 50%</u>

(if it odd <em>and</em> even then its 100%)

dalvyx [7]3 years ago
3 0

Answer:

100%

Step-by-step explanation:

There is a 100% chance rolling an odd or even since all the faces of this die are odd or even.

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Answer:can't see no 1

Step-by-step explanation:

2=A

3=c

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The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow
Reika [66]
If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now    \bf \begin{cases}&#10;A=l\cdot w\\\\\&#10;A=3000000\\&#10;----------\\&#10;3000000=l\cdot w\\\\&#10;\frac{3000000}{w}=l&#10;\end{cases}\qquad thus&#10;\\\\\\&#10;P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}&#10;\\\\\\&#10;P=3w+6000000w^{-1}\\\\&#10;-----------------------------\\\\&#10;now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}&#10;\\\\\\&#10;\textit{so the critical points are at }&#10;\begin{cases}&#10;0=w^2\\\\&#10;0=\frac{3w^2-6000000}{w^2}&#10;\end{cases}

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the 0=w^2\implies 0=w   so.  you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0
3 years ago
Would kindly appreciate the help please !
Trava [24]

Answer:

cannot be determined

Step-by-step explanation:

We do not know if any of the angles are equal and are only given two sides.

We cannot determine if the two triangles are similar

7 0
3 years ago
A planer is set to remove 1/16 inch from a board on each pass. If the board starts out at 3/4 inch thick how many passes would y
Pachacha [2.7K]
The answer would be 7 passes
7 0
3 years ago
Read 2 more answers
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
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