Y(y + 4) - y2 = 6
y2 + 4y - y2 = 6
4y = 6 ⇒ False
Answer:
21+/-sqrt(253)=x
So one value for x is 21+sqrt(253)
and another is 21-sqrt(253)
Problem:
Given (21,7) and (x,1), find all x such that the distance between these two points is 17.
Step-by-step explanation:
Change in x is x-21
Change in y is 7-1=6
distance^2=(change in x)^2+(change in y)^2
17^2=(x-21)^2+(6)^2
289=(x-21)^2+36
Subtract 36 on both sides:
289-36=(x-21)^2
253=(x-21)^2
Take square root of both sides:
+/-sqrt(253)=x-21
Add 21 on both sides:
21+/-sqrt(253)=x
Step-by-step explanation:
so, yes, the area of a triangle is
baseline × height / 2
so, we have here
16 = 8 × height / 2 = 4 × height
height = 16/4 = 4 in.
Answer:
A
Step-by-step explanation:
Its A because -4 - 3x > 7 because -1 - 7 is -6 but u have to - 1 because of the negative signs
