The ratio of the area of square PQRS to the area of square ABCD is 5/9
<h3>Area of square ABCD</h3>
Assume the measure of the side lengths of the square ABCD is 1, then the area of the square ABCD is:
See attachment for the diagram that represents the relationship between both squares.
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Pythagoras theorem</h3>
The measure of length PQ is then calculated using the following Pythagoras theorem:
Evaluate the squares
Add the fractions
<h3>Area of square PQRS</h3>
The above represents the area of the square PQRS.
i.e.
So, the ratio of the area of PQRS to ABCD is:
This gives
Hence, the ratio of the area of square PQRS to the area of square ABCD is 5/9
Read more about areas at:
brainly.com/question/813881
An equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
In this case, our y-intercept is 0, so we're left with y = -5x.
-5 is in the place of m, which means -5 is our slope.
The slope of y = -5x is -5.
Are there any answer choice
Answer:
sorry i dont understand
Step-by-step explanation: