36/20 or simplified and as a mixed number would be:
1 and16/20
It could be? the 7 could be 7 to literally any number soooo
Answer:
Step-by-step explanation:
Given that:
sample size n = 36
standard deviation = 10.1
level of significance ∝ = 0.10
The null hypothesis and the alternative hypothesis can be computed as follows:


The test statistics can be computed as follows:





degree of freedom = n - 1 = 36 - 1 = 35
Since this test is two tailed .
The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)
P - value = 2 × 0.435163515
P - value = 0.8703 ( to four decimal places)
Decision Rule : To reject the null hypothesis if P - value is less than the 0.10
Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.
Answer:
6 gallons per minute
Step-by-step explanation:
Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is
Q = a + bt ........... (1)
Now, Q(t = 0) is given to be 50 gallons.
So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).
Now, two points on the graph are (0,50) and (1,44).
So, the slope = b = = - 6 gallons per minute.
Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)
Use a percentage finder ;), also it will show you the work on some sites
;)