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3 years ago

Help pls please hmmm

Mathematics

2 answers:

hichkok12 [17]3 years ago

6 0

Step-by-step explanation:

Here is your answer

(2)⁴*³
2¹²

Softa [21]3 years ago

5 0

Answer:

2^12

Step-by-step explanation:

Since 2^4 is already powered you will only power the 4 and not the 2

For example (a^2)^3 = a^6

and not a*a*a^6

You only power the 2 and not the "a"

Hope this helps!

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He cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 5 units, and t

AleksandrR [38]

Answer:

The volume of the pyramid is not equal to the volume of the cylinder.

Step-by-step explanation:

A right cylinder has the circular cross-sectional area and if the cross-sectional areas of a right pyramid and a right cylinder are the same then the pyramid must be a right circular cone.

Now, the volume of a right cylinder is πr²h and that of a right circular cone is 1/3 πr²h.

Therefore, the radius of the base of the cone and that of the cylinder is the same and their heights are equal to be 5 units, then the volume of the pyramid is not equal to the volume of the cylinder. (Answer)

5 0

3 years ago

Which method is valid for proving that two circles are similar?

tatuchka [14]

'a', 'c', and 'd' are true for any two circles. That's because
ALL circles are similar. You don't need to prove it. The question
is weird.

4 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$