Answer:
15 25 25 65
10 05 20 35
25 30 45 100
First column is 6th grade, second is 7th, third is 8th and the last column is total
Answer:
![r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
Step-by-step explanation:
We need to isolate 'r'
To isolate 'r' , first multiply by 3 on both sides
divide by 4pi on both sides
Take cube root on both sides
![\sqrt[3]{\frac{3V}{4\pi}}= r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%3D%20r)
Answer:
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Class 9
>>Maths
>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
Bookmark
In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
463685
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Medium
Solution
verified
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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Answer:
$1171.05
Step-by-step explanation:
1500 × (1-(6 / 100))⁴
