The answer could possibly be D.) The product have more potential than the activated complex OR C.) Forming the activated complex requires energy .
2.26%, 26.8%, 2 2/5, 2.62, 271%
Hope this helps! :D
Answer:
a) Kb = 10^-9
b) pH = 3.02
Explanation:
a) pH 5.0 titration with a 100 mL sample containing 500 mL of 0.10 M HCl, or 0.05 moles of HCl. Therefore we have the following:
[NaA] and [A-] = 0.05/0.6 = 0.083 M
Kb = Kw/Ka = 10^-14/[H+] = 10^-14/10^-5 = 10^-9
b) For the stoichiometric point in the titration, 0.100 moles of NaA have to be found in a 1.1L solution, and this is equal to:
[A-] = [H+] = (0.1 L)*(1 M)/1.1 L = 0.091 M
pKb = 10^-9
Ka = 10^-5
HA = H+ + A-
Ka = 10^-5 = ([H+]*[A-])/[HA] = [H+]^2/(0.091 - [H+])
[H+]^2 + 10^5 * [H+] - 10^-5 * 0.091 = 0
Clearing [H+]:
[H+] = 0.00095 M
pH = -log([H+]) = -log(0.00095) = 3.02
Answer:
The answer is B, Alanine would be in the interior and serine would be on the exterior of the globular protein.
Explanation:
To further explain, the nature of solubility of side chain determines the position of the amino acid in the globular protein.
The hydrophilic amino acid such as serine are on the outside of the globular protein while the hydrophic amino acids such as leucine and alanine are on the interior of the globular protein.
This is why Alanine would be in the interior and serine would be on the exterior of the globular protein.
Cheers!
Answer:
Explanation:
Manganese is the element of group 7 and forth period. The atomic number of Manganese is 25 and the symbol of the element is Mn.
The electronic configuration of the element, manganese is -
To form 
, it will lose 3 electrons from the valence electrons and thus the configuration of the ion is:-
