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2 years ago

Convert the following quadratic from vertex form to standard form. Y=(x-1)^2-1

Mathematics

1 answer:

MArishka [77]2 years ago

4 0

In standard form: y= x^2 - 2x

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Adrianna can read 7 pages in 10 minutes. At this rate,how many pages can she read in 25 minutes

Westkost [7]

Use a proportion. 7/10 = x/25. Multiply 10 by 2.5 to get 25. Similarly, multiply 7 by 2.5 to get 17.5. 17 1/2 pages.

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3 years ago

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A woman buy a pair of shoes at a sale. She pays $60,saving $15 on the regular price. The percentage discount on the shoes is

IgorC [24]

Answer:

25 percent.

Step-by-step explanation:

15 is 1/4 of 60 and if she gets 1/4 off then that's equal to 25 percent

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3 years ago

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Can anybody help me please

Sliva [168]

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3 years ago

There is a 50% chance a coin lands on heads and a 50% chance the coin lands on tails what is the probability that the coin lands

Olegator [25]

Since the probability of the coin landing leads is 1/2, simply cube 1/2 to arrive at your answer: 1/8.

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3 years ago

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At an outpatient mental health clinic, appointment cancellations occur at a mean rate of 1.5 per day on a typical Wednesday. Let

Kamila [148]

Answer:

a) Cancellations are independent and similar to arrivals.

b) 22.31% probability that no cancellations will occur on a particular Wednesday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Mean rate of 1.5 per day on a typical Wednesday.

This means that $\mu = 1.5$

(a) Justify the use of the Poisson model.

Each wednesday is independent of each other, and each wednesday has the same mean number of cancellations.

So the answer is:

Cancellations are independent and similar to arrivals.

(b) What is the probability that no cancellations will occur on a particular Wednesday

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231$

22.31% probability that no cancellations will occur on a particular Wednesday

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3 years ago