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Snezhnost [94]
1 year ago
7

If a sample of a radioactive isotope has a half-life of 1 year, how much of the original sample will be left at the end of the s

econd year?
Physics
1 answer:
Tasya [4]1 year ago
4 0

Answer:

1/4 of the original

Explanation:

That would be TWO half lives:

1/2  * 1/2   = 1/4   <======= 1/4 would be left

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A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the
sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg

Since the frictional force f_k is equal to f_k=\mu_k N=\mu_k mg, then we have that the acceleration is:

a=\frac{\mu_k mg}{m}=\mu_k g

Now, from the definition of acceleration we get:

a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}

And, as the final velocity is zero because the box gets to a stop, we have:

t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}

Finally, we calculate the displacement:

x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm

This means that the box moves 7.29cm backwards relative to the belt.

4 0
3 years ago
Gyroscopic wander can be divided in to two categories, one is DRIFT, what is the other?
Tju [1.3M]

Gyroscopic wander can be divided into two categories and these are:

  1. Drift
  2. Topple

<h3>What is gyroscopic wander?</h3>

Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.

Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:

  • Drift
  • Topple

Read more on gyroscopic wander here: brainly.com/question/12168194

#SPJ12

4 0
2 years ago
A nuclear power plant operates at 40.0% efficiency with a continuous production of 1192 MW of usable power in 1.00 year and cons
Maurinko [17]

Answer:

the answer is in the picture below......

4 0
3 years ago
What three factors decide how much gravitational potential energy a body has?
nikdorinn [45]

Answer:

1. Mass

2. Height

3. Gravitational Force Field

Explanation:

The three factors that decide how much gravitational potential energy a body has are: 1) The mass of the body itself, 2) The relative height at which the body is, because gravitational force varies with height i.e distance away from earth surface. 3) and finally the strength of the gravitational field the body is in.

5 0
3 years ago
a photon with a wavelength of 2.29x10^-7 meters strikes a mercury atom in the ground state. the photon can be absorbed by the me
Anarel [89]
I just figured this out now.
First you would use the formula
Ephoton= hc/λ and substitute in the value's of plank's constant, the speed of light in a vaccum and the wavelength which will give you the energy in joules. Then you go to the reference table and solve for the energy used between the different levels for Mercury making sure to convert electron volts to jules. In the end the correct answer should be energy level D.
4 0
3 years ago
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