All categories

3 years ago

Which of the following is an element?

1 answer:

3 0

Oxygen is on the Periodic Table of Elements as a member of the chalcogen group. It is a chemical element represented by the symbol O.

B would've also been a right answer if it weren't for the Dioxide part.

But the answer is C. Oxygen.

You might be interested in

Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/

Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

$W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.$

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0

3 years ago

The area of the velocity time graph gives displacement of the body true or false?

mote1985 [20]

The area of the velocity time graph gives displacement of the body true or false?

The answer this is true.

8 0

3 years ago

Read 2 more answers

If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *

Anna11 [10]

I know that protons and neutrons are located at the center of an atom, so the correct answer is D

7 0

3 years ago

Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer

Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

$I' = I_{0}Cos^{2}\theta$ .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

$I'' = I'Cos^{2}\left ( 90-\theta \right )$

So,

$I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )$

$I'' = I_{0}Cos^{2}\theta Sin^{2}\theta$

$I'' = \frac{I_{0}}{4}Sin^{2}2\theta$

(b)

Now differentiate with respect to θ.

$I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta$

$I'' = \frac{I_{0}}{2}\times Sin 4\theta$

7 0

3 years ago

3. If you put flowers in water through what process does the water enter the steams ?

worty [1.4K]

Water travels through long, thin tubes running up from the roots through the stems and leaves called xylem.Water moves up the xylem through a process called capillary action.

Capillary action allows water to be pulled through the thin tubes because the molecules of the water are attracted to the molecules that make up the tube. The water molecules at the top are pulled up the tube and the water molecules below them are pulled along because of their attraction to the water molecules above them.

5 0

3 years ago