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Tamiku [17]
2 years ago
10

How many hydrogen bonds are between cytosine and guanine

Chemistry
1 answer:
Lerok [7]2 years ago
5 0

Answer:

Three

Explanation:

Three hydrogen bonds are between guanine and cytosine base pairs

Hopefully, that helps!

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An unknown liquid has a vapor pressure of 88 mmhg at 45°c and 39 mmhg at 25°c. What is its heat of vaporization?
Elis [28]

The relation between vapour pressure , enthalpy of vapourisation and temperature is

ln(\frac{P1}{P2} ) = \frac{deltaH}{R} (\frac{1}{T2} - \frac{1}{T1})

ln (88/ 39) = DeltaH / 8.314 (1 / 318 - 1 / 298)

0.814 = DeltaH / 8.314 (2.11 X 10^-4 )

DeltaH = -32.07 kJ


6 0
3 years ago
A student is told that both energy and mass must be conserved in every chemical reaction. She measures the mass of Hydrochloric
salantis [7]

Answer:

Explanation:

When we react Hydrochlorid Acid with zinc we have the following reaction:

2HCl(aq) + Zn(s) --> ZnCl2(aq) + H2(g)

The hydrogen gas formed is lost to the environment, so we can affirme that in the start we have the mass for all the H, Cl and Zn atoms in the solution, but after the reaction occurs, we have only the mass for the Cl and Zn atoms.

That's why the mass is less than the original.

The law that the student was told is only applied to closed environments.

6 0
3 years ago
Read 2 more answers
The si unit for measuring acceleration is?
ehidna [41]

m/s² aka meter per second squared.

acceleration = change in velocity/time  

= distance/time

--

time  

= m/s

--

s

=m/s^2

7 0
3 years ago
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Every Sunday, Sarah prepares blue fruit punch to
MrRissso [65]

Answer:

Fruit punch with a very dark blue color

Explanation:

8 0
3 years ago
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Many grams of aluminum are required to produce 3.5 moles Al2O3 in the presence of excess O2?
Aleks [24]
The  grams  of aluminum  that are required   to produce  3.5  moles of AlO3  in  presence of excess O2   is calculated as  below

write  the  equation for reaction
4 Al + 3O2 =2 Al2O3

by use of mole  ratio between  Al  to  Al2O3   which  is  4 :2  the moles of  Al 
=3.5 x4/2 = 7  moles

mass of Al  =  moles /   x molar mass

= 7 moles  x27 g/mol  =189  grams

4 0
3 years ago
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