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Vedmedyk [2.9K]
2 years ago
13

What is the molarity of a solution that contains 11.6 moles of LiNO3 in 13.7 liters of solution?

Chemistry
1 answer:
Tatiana [17]2 years ago
6 0

The molarity of this should be around 0.846

-----

Formula: M= mols/liters

-----

So… M= 11.6/13.7⇒ 0.846

-----

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100.0 g of liquid copper (molar mass 63.546 g/mol; melting point 1358 K; density 8.02 g/mL) is placed in a rigid container of vo
gtnhenbr [62]

Answer:

8.912x10^-18

Explanation:

-dn/dt = pANa/2piMRT

100 g = initial copper

Number of moles = 100/63.546

= 1.5736

Mass of copper left = 100-10.0168

= 89.9832

Moles = 89.9832/63.546

= 1.4160

dn = 1.4160-1.5736

= -0.1576

dt = 2 hrs

A = 3.23mm² = 3.23x10^-6

M = 63.546

T = 0.0821

T = 1508k

Na = 6.023x10²³

When we insert all these into the formula above

We get

P = 8.912x10^-18atm

4 0
3 years ago
Which of the following statements is correct concerning the class of reactions to be expected for benzene and cyclooctatetraene?
Sunny_sXe [5.5K]

Answer:

Both substances undergo substitution reactions.

Explanation:

Let us go back to the idea of aromaticity. Aromatic substances are said to possess (4n + 2) π electrons according to Huckel rule.

Aromatic substances are unusually stable and the aromatic ring can not be destroyed by addition reactions.

Since both benzene and cyclooctatetraene are both aromatic, they do not undergo addition reactions whereby the aromatic ring is destroyed. They both undergo substitution reaction in which the aromatic ring is maintained.

4 0
3 years ago
At a particular pressure and temperature, nitrogen gas effuses at the rate of 79 mL/s. Under the same conditions, at what rate w
amm1812

Rate of Sulfur dioxide : 2730.44 mL/s

<h3>Further explanation  </h3>

Graham's law: <em>the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  </em>

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

MW of N₂ = 28 g/mol

MW SO₂ = 64 g/mol

\tt 28\times 79^2=64\times r_2^2\\\\r_2^2=\dfrac{28\times 79^2}{64}=2730.44~mL/s

3 0
3 years ago
50 points - I need this really soon! plz help
kirill115 [55]

Answer:

C.

Explanation:

Butane (C4H10) has 3 C-C bonds in the carbon chain and 10 C-H bonds

7 0
3 years ago
When nutrients, water, and materials cross a cell membrane without requiring energy from the cell, the process is called
seraphim [82]
Answer

passive transport.

Explanation

the movement of substances across a cell membrane without the use of energy by the cell.
7 0
3 years ago
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