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2 answers:
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Given:
Perimeter of a rectangular paper = 22 inches.
Area of the rectangular paper = 28 square inches.
To find:
The dimensions of the rectangular paper.
Solution:
Let l be the length and w be the width of the rectangular paper.
Perimeter of a rectangle is:
Perimeter of a rectangular paper is 22 inches.
...(i)
Area of a rectangle is:
Area of the rectangular paper is 28 square inches.
Using (i), we get
Splitting the middle term, we get
Using zero product property, we get
If , then by using (i)
If , then by using (i)
Therefore, the dimensions of the paper are either or
.
We have to find the" ratio of the area of sector ABC to the area of sector DBE".
Now,
the general formula for the area of sector is
Area of sector= 1/2 r²θ
where r is the radius and θ is the central angle in radian.
180°= π rad
1° = π/180 rad
For sector ABC, area= 1/2 (2r)²(β°)
= 1/2 *4r²*(π/180 β)
= 2r²(π/180 β)
For sector DBE, area= 1/2 (r)²(3β°)
= 1/2 *r²*3(π/180 β)
= 3/2 r²(π/180 β)
Now ratio,
Area of sector ABC/Area of sector DBE =
= 4/3