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Sholpan [36]
2 years ago
15

Help with math pls cant figure it out

Mathematics
1 answer:
tatyana61 [14]2 years ago
7 0

Answer:

\frac{5}{4}+or-\frac{3i\sqrt{7} }{4}

Step-by-step explanation:

You can solve this equation with the quadratic formula which is:

m_{1,2}=\frac{-b+or-\sqrt{b^{2}-4ac } }{2a}

All you need to do is rearrange the equation (add -\frac{11}{2} to both sides and then multiply both sides by 2) to get:

2m^2-5m+11=0

From this new equation, we can easily see that a = 2, b = -5, and c = 11 AND you don't have to work with as many fractions. Substitute the values for a, b, and c into the quadratic formula to get:

m_{1,2}=\frac{5+or-\sqrt{(-5)^{2}-4(2)(11) } }{2(2)}

That simplifies to:

\frac{5}{4}+or-\frac{\sqrt{25-88} }{4}

Which simplifies even further to:

\frac{5}{4}+or-\frac{\sqrt{-63} }{4}

Which gets you:

\frac{5}{4}+or-\frac{3i\sqrt{7} }{4}

P.S. The plus-minus sign wasn't working for me, so I had to just write, "+or-". I hope that didn't make it too confusing for you.

P.P.S. Hope this helps :) Don't forget to mark Brainliest if it did.

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<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
What is the slope of a line perpendicular to the line whose equation is 2x-y=5 ?
mariarad [96]

Answer:

-1/2

Step-by-step explanation:

the slope of the line 2x-y=5 is 2

a perpendicular line has the negative reciprocal of the slope of the other line

hopefully this helps :)

3 0
2 years ago
Matthew's dad hired him to paint 6 wooden patio chairs for $125. It takes him 9 hours to paint all of the chairs. If it takes th
frozen [14]

Given:

Matthew's dad hired him to paint 6 wooden patio chairs for $125.

Time taken by him to paint all of the chairs = 9 hours.

It takes the same amount of time to paint each chair.

To find:

The fraction of an hour does it take Matthew to paint one chair

Solution:

Total time = 9 hours

Total number of chairs = 6

Now, time taken by Matthew to paint one chair is

\dfrac{\text{Total time}}{\text{Total number of chairs}}=\dfrac{9}{6}

\dfrac{\text{Total time}}{\text{Total number of chairs}}=\dfrac{3}{2}

Therefore, Mattew takes \dfrac{3}{2} of an hour to paint one chair.

Thinking with a model: On dividing the total time by total number of chairs we get time taken by Mattew (in hours) to paint one chair. So, the result represents the fraction of an hour taken by Matthew to paint one chair.

8 0
3 years ago
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Papessa [141]
The answer is
A. 90%
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3 years ago
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The best answer would be 46
5 0
3 years ago
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