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Andreyy89
2 years ago
6

Which of the following factors most affect the rate at which waves erode land features along the shore?

Physics
2 answers:
Art [367]2 years ago
8 0

Answer:

The biggest factor affecting coastal erosion is the strength of the waves breaking along the coastline. A wave's strength is controlled by its fetch and the wind speed. Longer fetches & stronger winds create bigger, more powerful waves that have more erosive power.

Explanation:

OLEGan [10]2 years ago
5 0

Answer:

The biggest factor affecting coastal erosion is the strength of the waves breaking along the coastline. A wave's strength is controlled by its fetch and the wind speed. Longer fetches & stronger winds create bigger, more powerful waves that have more erosive power.

Explanation:

hope it helps !

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Why are ionic solids poor conductors of electricity? The lattice is brittle. The ions are neutral. The ions are of equal but opp
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The ions are in fixed positions.

Explanation:

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6 0
4 years ago
A syringe of volume 16 cm3 is filled with air to a pressure of 1.03 atm. If the piston of the syringe is pushed to change the vo
denpristay [2]
<h3>Answer:</h3>

189.07 kPa

<h3>Explanation:</h3>

Concept tested: Boyle's law

<u>We are given;</u>

  • Initial volume of the syringe, V1 is 16 cm³
  • Initial pressure of the syringe, P1 is 1.03 atm
  • New volume of the syringe, V2 is 8.83 cm³

We are required to calculate the new pressure of the syringe;

  • We are going to use the concept on Boyle's law of gases.
  • According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.
  • That is; P α 1/V
  • At varying pressure and volume, k(constant)  = PV and P1V1=P2V2

Therefore, to get the new pressure, P2, we rearrange the formula;

P2 = P1V1 ÷ V2

     = ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³

    = 1.866 atm.

  • Thus, the new pressure is 1.866 atm
  • But, we need to convert pressure to Kpa
  • Conversion factor is 101.325 kPa/atm

Thus;

Pressure = 1.866 atm × 101.325 kPa/atm

               = 189.07 kPa

Hence, the new pressure of the air in the syringe is 189.07 kPa

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