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Marina86 [1]
3 years ago
9

How many mL of beakers u need in separating salt, sand, iron filings, and beads

Physics
1 answer:
grin007 [14]3 years ago
3 0

Explanation:

a 50-mL beaker with the same label.

hope it helps

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A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards
Lena [83]
Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh


8 0
3 years ago
Is the voltage of two identical lamps the same?​
Dahasolnce [82]

Answer:

It depends if they have the same lightbulb in them.

Explanation:

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this refers to the process of manufacturing that introduced powered machinery to the production of goods​
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This had to do with gain power and trade inequality business
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50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
xxTIMURxx [149]

Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)

4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
3 years ago
Hi, I need your help with this Physics exercise, I hope you can help me A pulse moving to the right along the x axis is represen
igomit [66]

Answer:

Velocity = 0.309 m/s

Along negative x axis

Explanation:

A pulse moving to the right along the x axis is represented by the wave function

y(x,t) = 2/ (x - 3t)² + 1

At t =0

y(x,0) = 2/ ((x - 3(0))² + 1)

        =2 / (x² + 1)

At t = 1

y(x,t) = 2/ ((x - 3(1))² + 1)

= 2 /(( x - 3)² + 1)

At t = 2

y(x,t) = 2/ ((x - 3(2))² + 1)

= 2 /(( x - 6)² + 1)

For the pulse with expression y(x,t) = 4.5e^{-(8.73x + 2.70t)}²

The Velocity is

V = 2.7 / 8.73

= 0.309 m/s

3 0
3 years ago
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