Answer:
Percent yield of reaction is 75%.
Explanation:
Given data:
Moles of A = 2.0 mol
Moles of B = 4.0 mol
Moles of C formed = 1.8 mol
Percent yield of reaction = ?
Solution:
Chemical equation:
2A + 5B → 3C + D
We will compare the moles of A and B with C from balance chemical equation.
A : C
2 : 3
B : C
5 : 3
4 : 3/5×4 = 2.4 mol
Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.
Percent yield:
Percent yield = actual yield /theoretical yield × 100
Percent yield = 1.8 mol / 2.4 × 100
Percent yield =75%
Answer:
Models help scientists understand processes in the natural world by providing simpler representations of those processes.
Answer:
In 33.7 grams SnF2 we have 8.17 grams of F
Explanation:
Step 1: Data given
Mass of SnF2 = 33.7 grams
Molar mass of SnF2 = 156.69 g/mol
Molar mass of F = 19.00 g/mol
Step 2: Calculate moles of SnF2
Moles SnF2 = mass / molar mass
Moles SnF2 = 33.7 grams / 156.69 g/mol
Moles SnF2 = 0.215 moles
Step 3: Calculate moles F
For 1 mol SnF2 we have 2 moles F
For 0.215 moles SnF2 we have 2*0.215 = 0.430 moles F
Step 4: Calculate mass F
Mass F = moles F * molar mass F
Mass F = 0.430 moles * 19.00 g/mol
Mass F = 8.17 grams
In 33.7 grams SnF2 we have 8.17 grams of F
Answer:
Make them go instinct
Explanation:
No one wants cats taking over the whole world
Answer: The answer is A. - 4.88x10^20 H2O2 molecules
Explanation: I hope this helps!
