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3 years ago

Genetics and reproduction

Chemistry

1 answer:

Zepler [3.9K]3 years ago

7 0

genetics and reproduction is all about dna.

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3 years ago

5. A grouping of organisms based on shared characteristics is called

lidiya [134]

Classification ,
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3 years ago

Read 2 more answers

Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.

mafiozo [28]

Answer:

= 8350 joules

Solution and explanation:

The heat of fusion refers to the quantity of heat released when a given amount of water freezes.

For example, 1 g of water releases 334 J when it freezes at 0°C.

Therefore; For 25.0 g of water.

Heat released = Mass of water × heat of fusion

= 25 g × 334 J/g

= 8350 Joules

Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.

5 0

3 years ago

A 1.78−L sample of hydrogen chloride (HCl) gas at 2.09 atm and 22°C is completely dissolved in 699 mL of water to form hydrochlo

patriot [66]

Answer:

$M=0.960M$

Explanation:

Hello,

In this case, it is firstly necessary to compute the dissolved moles of hydrogen chloride into the water as shown below:

$n_{HCl}=\frac{PV}{RT}=\frac{2.09atm*1.78L}{0.082\frac{atm*L}{mol*K}*295.15K}=0.671molHCl$

Thus, the molarity is computed as shown below:

$M=\frac{0.671mol}{0.699L}=0.960M$

Wherein no change in volume is considered, therefore the volume of the solution was the same volume of water.

Best regards.

5 0

3 years ago

How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL o

Rama09 [41]

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH = 0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

7 0

3 years ago