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3 years ago

A form of electricity which can attract things

1 answer:

8 0

A form of electricity which can attract things is static electricity. Static electricity is the result of an imbalance between negative and positive charges in an object. These charges built up o the surface of an object until they find a way to e released or discharged causing the attraction of things.

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What is the name of this hydrocarbon?

grandymaker [24]

It's Butane (C4H10)

it's an alkane (CnH2n+2)

good luck

6 0

3 years ago

Read 2 more answers

1. How many moles of HCl are in 7.80 X 1022 molecules? Answer:___0.13 moles of HCI

Nuetrik [128]

Answer: 7.80× $10^{22}$ $\frac{1}{6.02*10^{23} }$ =.13

Explanation:

8 0

3 years ago

7. How many moles are there in 4.6 gms of Sodium(Na)?

Marizza181 [45]

Answer:

0.2mol

Explanation:

mol = mass/mr

mass = 4.6g

mr = 23

mol = 4.6/23

= 0.2mol

7 0

3 years ago

The line graph shows the heights of plants grown in fertilized and unfertilized soil. Based on this information, what will most

Helen [10]

Answer:

g) Neither plant should increase by 1 cm in height.

Explanation:

See the graph for this question on the figure attached.

The growing of the plant A is represented by the line that goes above the other. At start, that line has a slope that rises about 0.75 cm ( height increase) in 1 day. From the day 2 and forward the slope of the line decreases. The line reaches its highest point about at day 4 and seems to start decreasing. Thus, you should predict that on the day six it most likely does not increase in height.

The growing of the plant B is represented by the line drawn below the other. As for the plant B, the growing decreases with the number of days. Between the days 4 and 5 the line is almost flat, which means that most likely this plant will not grow on the day six or grow less than 0.5 cm.

Thus, for both plants you can say that on day six, most likley, neither should increase by 1 cm in height (option g).

5 0

3 years ago

If 252 grams of iron are reacted with 321 grams of chlorine gas, what is the mass of the excess reactant leftover after the reac

mario62 [17]

Answer:

Iron is in excess.

1) The mass of the iron remaining = 83.38 grams

2) Ethane is in excess. There will remain 90.06 grams ethane

Explanation:

Step 1: Data given

Mass of iron = 252 grams

Mass of Cl2 = 321 grams

Molar mass of Fe = 55.845

Molar mass of Cl2 = 70.9 g/mol

Step 2: The balanced equation

2Fe(s)+3Cl2(g)⟶2FeCl3(s)

Step 3: Calculate moles

Moles = mass / molar mass

Moles Fe = 252.0 grams / 55.845 g/mol = 4.512 moles

Moles Cl2 = 321.0 grams / 70.90 g/mol = 4.528 moles

Step 4: Calculate the limiting reactant

For 2 moles Fe we need 3 moles Cl2 to produce 2 moles Fecl3

Cl2 is the limiting reactant. It will completely be consumed (4.528 moles).

Fe is in excess. There will 4.528 * 2/3 = 3.019 moles be consumed

There will remain 4.512 - 3.019 = 1.493 moles of Fe

The mass of the iron remaining = 1.493 * 55.845 g/mol =83.38 grams

If 152 grams of ethane (C2H6) are reacted with 231 grams of oxygen gas, what is the excess reactant?

Step 1: Data given

Mass of ethane = 152.0 grams

mass of O2 =231.0 grams

Molar mass of ethane = 30.07 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

2C2H6(g) + 7O2(g) ⟶ 4CO2(g) + 6H2O(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles ethane = 152.0 grams / 30.07 g/mol = 5.055 moles

Moles O2 = 231.0 grams / 32.0 g/mol = 7.22 moles

Step 4: Calculate limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed (7.22 moles).

Ethane is in excess. There will react 7.22 * 2/7 = 2.06 moles

There will remain 5.055 - 2.06 = 2.995 moles ethane

2.995 moles ethane = 2.995 * 30.07 g/mol = 90.06 grams ethane

8 0

4 years ago

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