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ira [324]
3 years ago
5

A form of electricity which can attract things

Chemistry
1 answer:
qwelly [4]3 years ago
8 0

 

A form of electricity which can attract things is static electricity. Static electricity is the result of an imbalance between negative and positive charges in an object. These charges built up o the surface of an object until they find a way to e released or discharged causing the attraction of things.

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How many grams of Hydrogen (H) would need to react with 143 grams of Oxygen (O) to make 235 grams of Water (H20)? 235
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Read 2 more answers
PLZ HELP I DONT KNOW HOW TO DO THIS!!!
koban [17]
#1  The Correct Answer is D

<span>D) The Distance Traveled by The Wave During One Full Cycle.

Ex. frequency, wavelength, amplitude and wave speed. Amplitude is measured in metres (m). The greater the amplitude of a wave then the more energy it is carrying. The wavelength, λ, of a wave is the distance from any point on one wave to the same point on the next wave along. 

(The symbol is a Greek letter, 'lambda'.)
  

 #2  The Correct Answer is B

</span><span>B) Police Siren 

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Mechanical waves require a medium in order to transport their energy from one location to another. A sound wave is an example of a mechanical wave. Slinky waves, water waves, stadium waves, and jump rope waves are other examples of mechanical waves; each requires some medium in order to exist. </span>
7 0
3 years ago
A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
4 years ago
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