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Elena L [17]
3 years ago
12

Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh

en reactants are in the presence of an enzyme. always gets absorbed and increases the potential energy of the final products. Two of the answers are correct. is used to break reactant bonds and/or make new product bonds.
Chemistry
1 answer:
daser333 [38]3 years ago
5 0

Answer:

is used to break reactant bonds and/or make new product bonds.

Explanation:

<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>

The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.

<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.

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3 years ago
What is the mass, in grams, of
DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2   MW = 32 + 2 = 34 g

                                    34g -------------------- 6.023 x 10²³ molecules

                                    x       -------------------  6.85 x 10 ²⁰

                                   x = (6.85 x 10 ²⁰)(34)/  6.023 x 10²³

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3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

                                    64 g -------------------- 6.023 x 10²³ molecules

                                    x      --------------------  3.3×1022 SO2 molecules

                                    x = (3.3×1022 SO2)(64) / 6.023 x 10²³

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5.5×1025 O3 molecules

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                                 48 g -----------------   6.023 x 10²³ molecules

                                  x     ------------------   5.5×1025 O3 molecules

                               x = (5.5×1025 )(48) /  6.023 x 10²³

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                              16 g --------------------  6.023 x 10²³ molecules

                              x      --------------------   9.30×1019 CH4 molecules

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                           x = 0.0025 g

4 0
3 years ago
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yuradex [85]

Answer:

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7 0
2 years ago
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Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
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so nitrogen must have +5 oxidation number... because sum all in formula must be 0.


4 0
3 years ago
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