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Elena L [17]
3 years ago
12

Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh

en reactants are in the presence of an enzyme. always gets absorbed and increases the potential energy of the final products. Two of the answers are correct. is used to break reactant bonds and/or make new product bonds.
Chemistry
1 answer:
daser333 [38]3 years ago
5 0

Answer:

is used to break reactant bonds and/or make new product bonds.

Explanation:

<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>

The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.

<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.

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horsena [70]
<span>2NaCN + (1)H2SO4 → Na2SO4 + 2HCN

</span><span>The coefficient of sulfuric acid is 1.</span>
3 0
3 years ago
Can someone please help me with this it's for a grade.
alukav5142 [94]

Answer:

The Answer is 'D'

Explanation:

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7 0
3 years ago
Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo
siniylev [52]

Answer:

∆H > 0

∆Srxn <0

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∆Suniverse <0

Explanation:

We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

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The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

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3 0
3 years ago
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mrs_skeptik [129]

Answer:

The answer to this question is D.

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