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Elena L [17]
3 years ago
12

Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh

en reactants are in the presence of an enzyme. always gets absorbed and increases the potential energy of the final products. Two of the answers are correct. is used to break reactant bonds and/or make new product bonds.
Chemistry
1 answer:
daser333 [38]3 years ago
5 0

Answer:

is used to break reactant bonds and/or make new product bonds.

Explanation:

<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>

The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.

<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.

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2N2 + O2 -------&gt; 2 N2O
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Answer:

Explanation:

Given data:

Mass of N₂ = 48.7 g

Moles of N₂ = ?

Molecules of N₂ = ?

Mass of N₂O = ?

Moles of N₂O = ?

Atoms of N₂O = ?

Solution:

Chemical equation:

2N₂ + O₂  →  2N₂O

Number of moles of N₂:

Number of moles = mass/ molar mass

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Number of moles = 1.74 mol

Number of molecules of N₂:

1 mole = 6.022 × 10²³ molecules

1.74 mol×  6.022 × 10²³ molecules/1 mol

10.5  × 10²³ molecules

Now we will compare the moles of N₂ with N₂O from balance chemical equation:

                 N₂             :           N₂O

                  2             :             2

               1.74            :           1.74

Moles of N₂O:  

1.74 mol

Mass of N₂O:

Mass = number of moles × molar mass

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Which state of matter is this:Particles vibrate and change positions
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Calculate the energy required to heat of 1.50 kg iron from -7.8 C to 15.0 C . Assume the specific heat capacity of silver under
Leni [432]

Answer : The energy required to heat of 1.50 kg iron is, 1.5\times 10^4J

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat required = ?

m = mass of iron = 1.50 kg  = 1500 g

c = specific heat of iron = 0.450J/g^oC

T_1 = initial temperature  = -7.8^oC

T_2 = final temperature  = 15.0^oC

Now put all the given value in the above formula, we get:

Q=1500g\times 0.450J/g^oC\times (15.0-(-7.8))^oC

Q=15390J=1.5\times 10^4J

Therefore, the energy required to heat of 1.50 kg iron is, 1.5\times 10^4J

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