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3 years ago

How much power does it take to do 500 J of work in 10 seconds?

Physics

1 answer:

Dmitry_Shevchenko [17]3 years ago

7 0

Power = work/time

= 500/10

= 50J/s or 50 watt

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A model train engine was moving at a constant speed on a straight horizontal track. As the engine moved along, a marble was fir

bagirrra123 [75]

Answer:

The marble was moving in a projectile and the speed of the engine was 2.716 m/s

Explanation:

The vertical component of the marble's flight path relative to the train

is given by the equation y(t) = v*t - (4.9)*t^2,

where, v is the initial upward velocity of the marble relative to the train.

So with y(1) = v - 4.9 = 0 we have

v = 4.9 m/s.

The marble will reach maximum height after 0.5 seconds, at which the

height will be y(0.5) = (4.9)*(0.5) - (4.9)*(0.5)^2 = (4.9)*(0.25) = 1.225 m.

Now, the marble has a vertical velocity component of 4.9 m/s and a horizontal velocity component

of V m/s such that tan(61) = 4.9 / V

V = 4.9 / tan(61) = 2.716 m/s

This horizontal velocity component of the marble is the same as the

speed of the train i.e. 2.716 m/s.

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3 years ago

Electrical power is transmitted from power plants to consumers–sometimes over very long distances– through conducting power line

sergeinik [125]

There is more wire to travel through,farther distance, and a higher possibility of other disruptions. Please Mark Brainliest!!!

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2 years ago

Question 3 Please, i need help! Thank you

Tom [10]

I don't know this 1 I'm sorry I can't help you

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3 years ago

Which planet weighs twice as much as all other planets.

Bumek [7]

Answer:

Jupiter. Although it is a gas planet, it has a ton of mass. Mass can determine the weight of an object. We can thereby assume that Jupiter weighs way more than most planets.

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1 year ago

Bus starts from rest if the acceleration of the bus is 0.5 MS squared what will be the velocity at the end of two minutes and wh

Nutka1998 [239]

Explanation:

Given that,

Initial speed of the bus, u = 0

Acceleration of the bus, a = 0.5 m/s²

Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.

So,

$a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s$

Let d is the distance cover during that time. So,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m$

So, the final speed is 60 m/s and the distance covered during that time is 3600 m.

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2 years ago