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Darya [45]
2 years ago
11

Pls help meh! im in 5 grd what is used to see white light? pls respond asap!

Physics
1 answer:
FinnZ [79.3K]2 years ago
7 0
L<span>ight with a spectral composition that stimulates all three types of the color sensitive </span>cone cells<span> of the </span>human eye<span> in nearly equal amounts appears white.





</span>
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how do i write this to where it is true? in the blue is a statement and the attached piece is false so i have to make it true an
OlgaM077 [116]

Answer:

cross out the false piece in blue and write the true piece in red

4 0
3 years ago
Two strings are adjusted to vibrate at exactly 202 Hz. Then the tension in one string isincreased slightly. Afterward, three bea
Semenov [28]

The concepts necessary to solve this problem are framed in the expression of string vibration frequency as well as the expression of the number of beats per second conditioned at two frequencies.

Mathematically, the frequency of the vibration of a string can be expressed as

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

Where,

L = Vibrating length string

T = Tension in the string

\mu = Linear mass density

At the same time we have the expression for the number of beats described as

n = |f_1-f_2|

Where

f_1 = First frequency

f_2 = Second frequency

From the previously given data we can directly observe that the frequency is directly proportional to the root of the mechanical Tension:

f \propto \sqrt{T}

If we analyze carefully we can realize that when there is an increase in the frequency ratio on the tight string it increases. Therefore, the beats will be constituted under two waves; one from the first string and the second as a residue of the tight wave, as well

n = f_2-f_1

f_2 = n+f_1

Replacing 3/sfor n and 202Hz for f_1,

f_2 = 3/s + 202Hz

f_2 = 3/s(\frac{1Hz}{1/s})+202Hz

f_2 = 206Hz

The frequency of the tightened is 205Hz

7 0
3 years ago
Little Tammy lines up to tackle Jackson to (unsuccessfully) prove the law of conservation of momentum. Tammy’s mass is 34.0 kg a
Leya [2.2K]

Answer:

So Tammy must move with speed 4.76 m/s in opposite direction of Jackson

Explanation:

As per law of conservation of momentum we know that there is no external force on it

So here we can say that initial momentum of the system must be equal to the final momentum of the system

now we have

m_1v_1 + m_2v_2 = 0

final they both comes to rest so here we can say that final momentum must be zero

now we have

34 v + 54 (3 m/s) = 0

v = -4.76 m/s

6 0
3 years ago
PLEASE HELP ME I AM TIMED!
cupoosta [38]
I believe the answer is D
3 0
2 years ago
According to the first rule, if a force pulls on one end of a rope, the tension in the rope equals the magnitude of the pulling
mixer [17]

Answer:

F.

Explanation:

Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.

magnitude of tension in rope 1 is

T1= F

Hence the tension T1 is rope 1 is F.

5 0
3 years ago
Read 2 more answers
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