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Kobotan [32]
3 years ago
9

ILL GIVE YOU BRANNIEST Two linear functions are shown. Linear function J is represented by the equation, y= 3/4 — 6 The table re

presents linear function K.
Which function has a larger x-intercept and what is its x-intercept?

A.
Linear function J has a larger x-intercept of –6.

B.
Linear function J has a larger x-intercept of 8.

C.
Linear function K has a larger x-intercept of 5.

D.
Linear function K has a larger x-intercept of 10.
Mathematics
1 answer:
algol133 years ago
7 0

Answer: -6

Step-by-step explanation:

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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27
german

Answer:

n = 78

Step-by-step explanation:

IQR is the interquartile range of the data set.

So Saul had already arranged the data in order, that is the first step when calculating the interquartile range.

25, 30, 50, 50, 50, 50, 56, n., 250

Next, is to find the median so we could easily separate the data into quartiles.

The median of the data 25, 30, 50, 50, 50, 50, 56, n., 250 = 50

Then, arrange the data into the first quartile and the third quartile

first quartile = 25, 30, 50, 50

third quartile = 50, 56, n., 250

first quartile median = 30 + 50 = 80/2 = 40

third quartile = 56 + n /2

The interquartile range formula is the first quartile subtracted from the third quartile:

IQR = Q3 – Q1.

Since 27 is the interquartile range, n=

27 = (56 + n /2) - 40

Use 2 to multiply through to eliminate the denominator

54 = (56 + n) - 80

n = 78

5 0
3 years ago
What’s the speed limit in mph for a speed limit of 75 kph
irga5000 [103]

Answer:

46.6 mph

Step-by-step explanation:

1 Kph is .6213 mph

6 0
3 years ago
What is 6 divided by 25.2
mr_godi [17]
6/25.2
Multiply both sides by 5 so 25.2 is a whole number:
30/126
and then simplify by dividing by 6: 
5/21 which is equal to 0.2381.

Hope this helps :)
6 0
3 years ago
Evaluate the expression.
EastWind [94]

Answer:

42

Step-by-step explanation:

We use (BODMAS) :

Brackets

Order/Index

Division

Multiplication

Addition

Subtraction

Now we do bracket first :

7(3²) = 7(9) = 63

Now we do division :

63÷3 = 21

Now we do multiplication :

2 × 21 = 42

Hope this helped and have a good day

4 0
2 years ago
Read 2 more answers
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
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