The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
c) 28°, 76°, 76°
Step-by-step explanation:
The two remote interior angles sum to 152°. Since they are congruent, their measures are 152°/2 = 76°. The adjacent interior angle is the supplement of 152°, so is 180°-152° = 28°.
The interior angles are 28°, 76°, 76°. . . . . matches choice C
Answer:
Use simultaneous equation for this problem
y= number of adults
x = number of children
3y + 2x = 160
y + x = 60
then we double the second equation
3y + 2x = 160
2y + 2x = 120
we cancel x by elimination
3y - 2y = 160 - 120
y = 40
Step-by-step explanation:
hope this helps
Answer:
135°+97°+x=180°. 232°+x=180°. x=232-180=102°
:x=102°
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
