Ask question

Ask question

All categories

3 years ago

5

If 3 2/5 is the lesser number in an inequality, which statement is true?

1 answer:

Elena L [17]3 years ago

8 0

Answer:

B is correct

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

You might be interested in

The bearing from the Pine Knob fire tower to the Colt Station fire tower is N 65° E, and the two towers are 31 kilometers apart.

suter [353]

The distance are

a. 42.42

b. 15. 52

<h3>How to solve for the distance</h3>

80 = 65 + <ABC

<ABC = 80 - 65

= 15

Through the use of sine rule we would have

By using sine rule,

Sine 15/a = sine 135/b =

sin 30/30.

Next we have to solve b by cross multiplying

b = (30× sin135) / sin 30

= 21.21/0.5

b = 42.42 km

Also, the value of a will be:

= (42.42 × sin 15) / sin 135

= 10.98/0.7071

= 15.52

Read more on bearing here:

brainly.com/question/15221233

#SPJ1

3 0

2 years ago

A rectangular solid and a cube are of equal volume. If the rectangular solid is 20 centimeters long, 5 centimeters wide, and 10

abruzzese [7]

Answer:

10 centimeters.

Step-by-step explanation:

First, we need to remember what's the formula to get the volume of a rectangular solid and a cube.

The volume of the first equals:

Volume = Length x Width x Height

While the volume of the cube is:

$Volume = a^{3}$ where a is the edge.

We are given the measures of the rectangular solid so we can calculate its volume:

$Volume= (20)(5)(10)=1000$ cubic cms.

Now, we know that both the volume of the rectangular solid and the cube are the same so we will use this information to calculate the edge of the cube.

$1000=a^3 \\\sqrt[3]{1000} =\sqrt[3]{a^3} \\10=a$

Thus the length of an edge of the cube is 10 centimeters

5 0

3 years ago

Alex runs on the track at school each weekday morning. If he runs 5.9 miles each day,about how much does he run every month?

Molodets [167]

Its just 20 x 5.9 = 118 simple

7 0

3 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

$\text{Minimum value }= 53$

$Q_1=62$

$Median=80$

$Q_3=86$

$\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

For second box plot

$\text{Minimum value }= 56$

$Q_1=62$

$Median=74$

$Q_3=89$

$\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value. It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range. It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0

3 years ago

What is the area of a cross section that is parallel to face CDHG ?

Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

$Length\times breadth\\\\=36\times 12\\\\=432\ cm^2$

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0

3 years ago

Read 2 more answers