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2 years ago

What is the product One-fifth times 2? Use the visual model to answer the question.

Mathematics

1 answer:

crimeas [40]2 years ago

5 0

Answer:

The answer is Two-fifths

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Kristen has 64 coins in her piggy bank. she has $9.25 in dimes and quarters. how many dimes and quarters does she have.

IRISSAK [1]

I believe she has 25 dimes in quarters and the rest in which is 9.00 in quarters

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2 years ago

Exercise #1: The amount of money in Nicole's bank account can be represented by the function f(x) = 32.50x + 200,

kolezko [41]

The initial amount in the account was $200 (y intercept). She adds $32.50 each day to her bank account (slope).

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2 years ago

Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash

VashaNatasha [74]

1 hour and 1/3rd of an hour

so A is right

4 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

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2 years ago

A store pays $996 for a barbecue grill and marks the price up by

mars1129 [50]

Just saying this but don't go to that store! The answer, by the way is $1494

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2 years ago