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2 years ago

Find the real solution(s) of the equation 1/6x^3 = -36

Mathematics

1 answer:

ratelena [41]2 years ago

3 0

Answer:

Below.

Step-by-step explanation:

1/6x^3 = -36

Multiply both sides by 6:

x^3 = -216

x = ∛(-216)

= -6.

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Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i

Marina86 [1]

Step 1 ) Move all terms right side of the equation.

$\displaystyle\ x^{2} + 6x = -18$

$\displaystyle\ x^{2} + 6x + 18 = -18 + 18$

$\displaystyle\ x^{2} +6x + 18 = 0$

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

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$\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}$

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$\displaystyle\ x = \frac{-6+6i}{2}$ ,

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Since the options only provide one of the answer we found, the answer is...

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•

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