(2x+4)/3 + (x+2)= 20 Multiply everything by 3 to eliminate the fraction (3/1)((2x+4)/3) + (3)(x+2)= (3)(20) 2x+4+3x+6= 60 5x+10=60 Subtract 10 from both sides 5x=50 divide both sides by 5 x=10
Check: Substitute answer in original equation (2x+4)/3 + (x+2)= 20 (2(10)+4)/3+(10+2)= 20 (20+4)/3+12= 20 24/3+12= 20 8+12= 20 20=20