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docker41 [41]
3 years ago
11

A number doubled and has four added to it. The result is divided by three and then added to the product of the original number a

nd two. The resulting sum is twenty.
Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
X= a number

(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10

Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20

Hope this helps! :)
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