<h2>
Answer:</h2>
The graph is shown in the Figure below
<h2>
Step-by-step explanation:</h2>
In this exercise, we have an equation. On the left side we have a straight line with slope 
and there is no any y-intercept. On the right side, on the other had, we also have a straight line, but the slope here is 
. Therefore, by plotting these two straight lines, we have that the solution is the origin, that is, the point 
.
Thats either 7/5 or 1 2/5 but since theres a whole number i think its 1 2/5
Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× 
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = 
× 100
% change in stopping distance = 7.34 %
Answer: what is your question, is this your question bro
Step-by-step explanation:
Answer:
Given: y = x2 + 4x – 5
Find the following
y-intercept
x-intercepts or the zeros of the functions or roots
graph of the function, given vertex is at (-2, -9)
Solve the system of linear equations – x + 6y = 8 2x + 5y = 3
Write the names of curves, given their equations:
x2/16 + y2/9 = 1
3y = 2x + 5
(x - 5)2 + (y + 6)2 = 25
x2/16 – y2/25 = 1
y = 2x2 + 10x + 25
Write down the first five terms of the arithmetic progression with the first term 8 and common difference 7, then find the 17th
Write down the first five terms of the geometric progression with the first term 3 and common ratio 2, then find the 17th
