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2 years ago

14

Carlos bought a new cell phone. The graph represents the

1 answer:

Hoochie [10]2 years ago

3 0

Answer:

B : y = 0.1x + 5

Step-by-step explanation:

using the y = mx + b equation

b is the intercept on the y axis ( x = 0)

m is the slope of the line.

From the graph we can see that the intercept is (0,5), therefore b = 5;

To calculate slope (m) pick two pints on the line e.g (100, 15) and (0, 5)

m = (y2 - y1)/(x2 -x1) = (15 - 5)/(100 - 0) = 10/100 = 0.1

m = 0.1

therefore in y = mx + b

y = 0.1x + 5

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Find the value of x. Round to the nearest degree.

marta [7]

Answer:

<u>x = 39°</u>

Step-by-step explanation:

The opposing side and the hypotenuse for the angle are given.

Remember, when the opposing side and the hypotenuse are given, take the cos ratio.

cosx = 7/9
x = cos⁻¹ (7/9)
x = 38.9424413°
<u>x = 39°</u>

6 0

2 years ago

What are all real square roots of .027

mario62 [17]

Answer:

Step-by-step explanation:

The principal, real, root of:

$^{2} \sqrt{0.027}$

= 0.164316767

All roots:

0.164316767

−0.164316767

0.027 is not a perfect square

5 0

3 years ago

Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°

kupik [55]

We have to break each degree in terms of 90

A) $sin180^\circ=sin(90\times2+0)$

Which is in third quadrant, therefore sine is negative hence

$sin(90\times2+0)= -sin0 ^\circ = 0$

B) $cos180^\circ =cos(90\times2+0)$

Which is in third quadrant, therefore cosine is negative hence

$cos(90\times2+0)= -cos0^\circ = -1$

C) $tan180^\circ=tan(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$tan(90\times2+0)= tan0^\circ = 0$

D) $csc180^\circ=csc(90\times2+0)$

Which is in third quadrant, therefore cosec is negative hence

$cosec(90\times2+0)= -csc0^\circ =$ not defined

E) $sec180^\circ=sec(90\times2+0)$

Which is in third quadrant, therefore secant is negative hence

$sec(90\times2+0)= -sec0^\circ = -1$

F) $cot180^\circ=cot(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$cot(90\times2+0)= cot0^\circ =$ not defined

Hence only $cos 180^\circ$ and

$sec180^\circ$ have value -1

Hope this will help

7 0

3 years ago

1. What is the probability of rolling a number less

Darina [25.2K]

Answer:

1/2

Step-by-step explanation:

There are 2 numbers less than 3. (1 and 2) and one 6 on a dice. Therefore there is a 3 out of 6 chance of rolling one of these 3 numbers (1, 2, and 6). This can be represented as 3/6 which would simplify to 1/2 or 50%.

It can also be found this way...

Probability = Number of desired outcomes ÷ number of possible outcomes. Therefore 3 ÷ 6 = 0.5 which is equal to 50% or 1/2.

I hope you choose my answer so you do well on your assignment! I've gotten an A in math every year :)

3 0

3 years ago

Read 2 more answers

If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?

Oduvanchick [21]

$\large\underline{\sf{Solution-}}$

<u>Given:</u>

$\rm \longmapsto x = a \sin \alpha \cos \beta$

$\rm \longmapsto y = b \sin \alpha \sin \beta$

$\rm \longmapsto z = c\cos \alpha$

Therefore:

$\rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta$

$\rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta$

$\rm \longmapsto \dfrac{z}{c} = \cos \alpha$

Now:

$\rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} }$

$\rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha$

$\rm = 1$

<u>Therefore:</u>

$\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1$

5 0

3 years ago