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Murljashka [212]
3 years ago
10

Why can different numbers of metal and monkeys atoms create ionic bonds together?

Chemistry
1 answer:
Lerok [7]3 years ago
3 0

Answer:

i'm assuming you meant to say nonmetal atoms... in an ionic bond, electrons from the metal are transferred to the nonmetal. The reason why different numbers of metal and nonmetal atoms can combine is so their charges cancel out. take CaCl2 for example. There are two chlorine atoms for every calcium atom. If it was just CaCl, the charges wouldn't cancel out since calcium has a charge of 2+ and chlorine has a charge of 1-. Therefore to balance the compound, you need two chlorines.

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What net ionic equation describes the reaction between Pb(NO3)2(aq) and Na2CO3(aq)?
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Answer:

Pb⁺²(aq) + CO₃⁻²(aq) →  PbCO₃ (s)

In net ionic equation we cancel the ions that have equal moles on both sides so  Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.

Explanation:

Net ionic equation:

In net ionic equation we only write the ions that are involved in reaction. If the system have same moles of ions in initial and final stages we cancel them as they have the same amount and are present in ionic form in the reaction medium. To formulate an ionic equation we just cancel the ions which have the same moles in initial and final stages.

Chemical equation:

Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + NaNO₃ (aq)

Balanced chemical equation:

In a balanced chemical equation we write the reactants and products in molecular form with number of moles.

Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + 2NaNO₃ (aq)

Ionic equation:

In ionic equation we write the equation in ionic form. It involves all the ions which will produce when we add any ionic compound in reaction medium.

Pb⁺² +2NO₃⁻¹ + CO₃⁻² + 2Na⁺¹  → PbCO3 (s) + 2NO₃⁻¹ (aq) + 2Na⁺¹ (aq)

Net ionic equation

In net ionic equation we cancel the ions that have equal moles on both sides. As we can see in the above ionic equation that Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.

Pb⁺²(aq) + CO₃⁻²(aq)  → PbCO₃ (s)

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