First solve the mass of 37.9 L seawater
M = 37.9 L ( 1000 ml / 1L ) ( 1.03 g / ml)
M = 39037 g
Then convert it to lb
M = 39037 g ( 1 lb / 453.592 g)
M = 86.06 lb
<span>Total weight = 86.06 lb + 59.5 lb = 145.56 lb so it can
support the aquarium</span>
Answer:
I think the answer is coming up with questions based on observations and reasoning
<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:

Or,

where,
= 
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:

Hence, the freezing point of solution is 2.6°C
Phosphorus!!!! Hope this helps