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marshall27 [118]
3 years ago
7

Which of the following is a precipitation reaction?

Chemistry
2 answers:
fredd [130]3 years ago
3 0

Answer:

B is a precipitation reaction.

Explanation:

This is because a precipitation reaction is when a solid is made from the combination of cations and anions in a solution to create a solid.

suter [353]3 years ago
3 0

Answer:

b. 2 NaI_{(aq)} + Hg_2(NO3)_{2(aq)} ---> Hg_2I_{2(s)} + 2 NaNO_{3(aq)}

Explanation:

<em>Precipitation reaction is a form of chemical reaction in which an insoluble salt (a precipitate) is formed from an aqueous mixture of two soluble salts.</em>

This thus means that:

  • The two reactants in a precipitate reaction must be in aqueous forms
  • At least, one of the products must be a solid (precipitate)

From all the options, only option b fulfills the conditions for a precipitate reaction.

The correct answer is b.

You might be interested in
Identify the compound with the highest magnitude of lattice energy. Identify the compound with the highest magnitude of lattice
Galina-37 [17]

Answer: Option (c) is the correct answer.

Explanation:

According to the Born-Lande equation,

          E = \frac{N_{A}Mz^{+}z^{-}e^{2}}{4 \pi \epsilin_{o} r}

where,   N_{A} = Avogadro's constant

                    r = distance between the anion and cation

                   M = Medlung constant

           z^{+} = charge on the cation

           z^{-} = charge on the anion

                  E = lattice energy

According to this expression, lattice energy is inversely proportional to the distance between the cation and anion. And, when we move down a group then there occurs an increase in the atomic radii of the atoms.

As a result, there will occur a decrease in their lattice energy. Since, the anionic part is same in all the given species but the cationic part is different.

In MgBr_{2} the size of magnesium cation is smaller than calcium, barium and strontium ion. Hence, there will be least distance between Mg and Br ions.

Thus, we can conclude that the magnitude of lattice energy will be the highest in MgBr_{2}.

4 0
3 years ago
How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lo
riadik2000 [5.3K]

Answer : The energy removed must be, -67.7 kJ

Solution :

The process involved in this problem are :

(1):C_6H_6(g)(425.0K)\rightarrow C_6H_6(g)(353.0K)\\\\(2):C_6H_6(g)(353.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(3):C_6H_6(l)(353.0K)\rightarrow C_6H_6(l)(335.0K)

The expression used will be:

\Delta H=[m\times c_{p,g}\times (T_{final}-T_{initial})]+m\times \Delta H_{vap}+[m\times c_{p,l}\times (T_{final}-T_{initial})]

where,

\Delta H = heat released by the reaction = ?

m = mass of benzene = 125 g

c_{p,g} = specific heat of gaseous benzene = 1.06J/g^oC

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC

\Delta H_{vap} = enthalpy change for vaporization = 33.9kJ/mole=33900J/mole=\frac{33900J/mole}{78.11g/mole}J/g=434.0J/g

Molar mass of benzene = 78.11 g/mole

Now put all the given values in the above expression, we get:

\Delta H=[125g\times 1.06J/g.K\times (353.0-(425.0))K]+125g\times -434.0J/g+[125g\times 1.73J/g.K\times (335.0-353.0)K]

\Delta H=-67682.5J=-67.7kJ

Therefore, the energy removed must be, -67.7 kJ

4 0
2 years ago
1.For Structure B the bond between carbon and sulfur is polar or non polar
Inga [223]

Answer:

polar

Explanation:

because carbon and sulfur have different electronegativities, the S=C bond is polar.

The entire molecule is nonpolar however because the dipoles (polar bonds) cancel out due to the geometry of the molecule (linear)

3 0
2 years ago
What are three forms of the element carbon?
german

Answer:

There are at least eight forms of carbon: amorphous, graphite, diamond, fullerenes, aggregated diamond nanorods, carbon nanofoam, glassy carbon, and linear acetylenic carbon.

Explanation:

3 0
3 years ago
How much heat in j is giving out when 85.0g of lead cools from 200.0 c to 10.0c
photoshop1234 [79]

Answer:

q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.

Explanation:

The Specific Heat capacity of Lead is 0.128 \frac{J}{g\ ^{0}C}

This means, increase in temperature of 1 gm of lead by 1 ^{0}\ C will require 0.128 J of heat.

Formula Used :

q = m.c.\Delta T

q = amount of heat added / removed

m = mass of substance in grams = 85.0 g

c = specific heat of the substance = 0.128

q = m.c.\Delta T = Change in temperature

                                          = final temperature - Initial temperature

                                          = 10 - 200

                                          = -190 ^{0}\ C

put value in formula

q = -  85\times 0.128\times 190

On calculation,

q = - 2067.2 J

- sign indicates that the heat is released in the process

5 0
3 years ago
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