<span>Ionic bonding between sodium and phosphate ions.</span>
Given the molar mass of Nitrogen is 14.01g/mol you can use that to solve for the moles of nitrogen.
0.235g(1mol/14.01g) = .0168 moles.
Answer:
Explanation:40 mph = 64.3738 kph
kph/3.6 = m/s
64.3738/3.6 = 17.8816 m/s
30 mins in seconds = 30 x 60 = 1800 s
1800 s x 17.8816 m/s = 32186.88 m or 32.18688 km or 20 miles
Answer:
513.74 g of solution
Explanation:
% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.
The relationship is:
3.64 g of potassium nitrate _____ 100 g solution
18.7 g of potassium nitrate _____ X = 513.74 g of solution
Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution
So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.
Answer:
The atomic mass of element is 65.5 amu.
Explanation:
Given data:
Abundance of X-63 = 50.000%
Atomic mass of X-63 = 63.00 amu
Atomic mass of X-68 = 68.00 amu
Atomic mass of element = ?
Solution:
Abundance of X-68 = 100-50 = 50%
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (50×63)+(50×68) /100
Average atomic mass = 3150 + 3400 / 100
Average atomic mass = 6550 / 100
Average atomic mass = 65.5 amu.
The atomic mass of element is 65.5 amu.
