All categories

2 years ago

12x(8x-20)÷4(2x-5) please solve it

Mathematics

1 answer:

Basile [38]2 years ago

8 0

Answer: 48 $x^{3}$ -240 $x^{2}$ +300x

hopes this helps

You might be interested in

Will give brainliest answer please help

Oxana [17]

Answer:

$a^{2}(24a^{2}+36a+12)$

Step-by-step explanation:

Area of rectangle= Length*Width

so $(6a^{2}+9a+3)*4a^{2}$ multiply each coefficient of a times 4a^2

$24a^{4}+36a^{3}+12a^{2}$ then take a^2 common factor so it will be

$a^{2}(24a^{2}+36a+12)$ =area

3 0

3 years ago

Question on Pic Thank You!!!

Bess [88]

A) >
B) =
C) >

Hope this helps!!
Also please could I have brainly?!

6 0

2 years ago

Read 2 more answers

P - 13 = 29<br> Can anyone help me with this

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

p - 13 = 29

Add 13 to both sides.

p - 13 + 13 = 29 + 13

p = 42

3 0

3 years ago

Read 2 more answers

The end points of a diameter of a circle are (6,2) and (-4,7).

nata0808 [166]

Answer:

Step-by-step explanation:

The standard form equation of a circle with radius r is expressed as

( x − h )^2 + ( y − k )^2 =r ^2 ,

where r represents the radius

h and k are the coordinates of the center of the circle C( h , k )

To determine the coordinates at the center of the circle, the midpoint formula would be used. It is expressed as

[(x1 + x2)/2 , (y1 + y2)/2]

Midpoint of the circle =

(6 - 4)/2 , (2 + 7)/2 = (1, 4.5)

h coordinate of the center = 1

k coordinate of the center = 4.5

r^2 = (x - h)^2 + (2 - k)^2

r^2 = (6 - 1)^2 + (2 - 4.5)^2

r^2 = 5^2 + (- 2.5)^2 = 25 + 6.25

r^2 = 31.25

Substituting r^2 = 31.25, h = 1 and k = 4.5 into (x − h )^2 + ( y − k )^2 = r^2, the standard equation of the circle becomes

(x − 1 )^2 + ( y − 4.5 )^2 = 31.25

8 0

3 years ago

A superhero is trying to leap over a tall building. The function f(x)=-16x^2+200x gives the superhero's height in feet as a func

Gemiola [76]

Answer:

Since $\bigtriangleup \geq 0$ , the superhero makes it over the building.

Step-by-step explanation:

The height is given by the following function:

$f(x) = -16x^{2} + 200x$

Will the superhero make it over the building?

We have to find if there is values of x for which f(x) = 612.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

If $\bigtriangleup < 0$ , the polynomial has no solutions.

In this question:

$f(x) = -16x^{2} + 200x$

$-16x^{2} + 200x = 612$

$16x^{2} - 200x + 612 = 0$

We have to find $\bigtriangleup$

We have that $a = 16, b = -200, c = 612$ . So

$\bigtriangleup = (-200)^{2} - 4*16*612 = 832$

Since $\bigtriangleup \geq 0$ , the superhero makes it over the building.

7 0

3 years ago

12x(8x-20)÷4(2x-5) please solve it​

12x(8x-20)÷4(2x-5) please solve it