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stira [4]
3 years ago
11

50 PTS!!!! No links pls! What is a title name for Aerobic cellular respiration?

Chemistry
2 answers:
Alex777 [14]3 years ago
6 0

Answer:

The chemical process in which oxygen is used to make energy from carbohydrates (sugars). Also called aerobic metabolism, cell respiration, and oxidative metabolism.

I am sorry if this isn't the answer you were hoping for so if it isn't, I greatly apologize.

I can change it to the correct one if you want

Sedbober [7]3 years ago
5 0

Answer:

Like another name?

Aerobic cellular respiration is also called aerobic metabolism, cell respiration, and oxidative metabolism.

Explanation:

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Base your answer to this question on the information below.
marusya05 [52]

can 37 93=53-32=65y 6

7 0
3 years ago
Do isomers have the same physical properties? Provide evidence.
Free_Kalibri [48]

Not necessarily.

<h3>Explanation</h3>

Isomers might differ in polarities. They will end up with different physical properties such as melting points.

Example:

  • 1,2-dichlorobenzene  has a melting point of around -18 ~ -17 degrees celsius. (SynQuest)
  • 1,4-dichlorobenzene (with two chlorine opposite to each other on a benzene ring) has a melting point of 52 ~ 54 degrees celsius. (SynQuest)

Both 1,4- and 1,2-dichlorobenzene contains two chlorine atoms connected to a benzene ring. The two molecules are structural isomers.

The two chlorine atoms are adjacent to each other in the 1,2 isomer. The molecule is asymmetric and polar.

The two chlorine align with an axis of symmetry in the 1,4 isomer. The molecule is symmetric. The dipoles would cancel out to produce a nonpolar molecule.

Dipole-dipole interactions are typically stronger than <em>induced</em> dipole<em> </em>in isomers. As a result, the 1,2 isomer has a higher melting point.

7 0
3 years ago
1. What are the effects of the collision forces when objects with different masses collide?
topjm [15]

Answer:one object to speed up (gain momentum) and the other object to slow down (lose momentum).

Explanation:

WW

5 0
3 years ago
The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?
soldier1979 [14.2K]

Answer: Volume of 1g of pure gold v=0.05181 \mathrm{cm}^{3}

Given;

Density of a pure gold=19.3 g / c m^{3}

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

     \rho=m / v

Where \rho=density of pure gold

           m=mass of pure gold

          v=volume of pure gold

From the above equation volume can be calculated as

v=m / \rho

Substitute the values of mass and density value in the above equation

v=1 / 19.3

v=0.05181 \mathrm{cm}^{3}

Result:

Thus the volume of 1g of pure gold is v=0.05181 \mathrm{cm}^{3}

8 0
3 years ago
1. What do the ice ages tell us about how Earth's<br> climate has changed in the past?
Levart [38]

Answer:

During ice ages, the most characteristic change to the planet has been the formation and spread large ice sheets and glaciers across much the Northern Hemisphere.

3 0
3 years ago
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