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Law Incorporation [45]
2 years ago
6

What is the volume of 2.0 mol CO2 at STP?

Chemistry
1 answer:
Andrew [12]2 years ago
6 0

Answer:

44.8 litres is the answer to the question

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Which of the following statements are FALSE of models? (select all that applies)
ira [324]

Answer:

A B and C

Explanation:

Hopefully this helps

7 0
3 years ago
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
2 years ago
The number of un paired electrons in the outer subshell of a cl atom is
Tatiana [17]
1 is the number of unpaired electrons in the outer subshell of a Cl atom
3 0
3 years ago
Pls help question 2 ill attach a picture​
Finger [1]

Answer:

X 154

Check solution in explanation

Explanation:

Average atomic mass = ( mass 1× abudance) + ( mass 2× abudance)+ ( mass 3× abudance) / 100

(149×13.8)+(152×44.9) +(154×41.3)/100

2056.2 + 6824.8 + 6360.2/100

=152.412

8 0
3 years ago
If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w
balu736 [363]

Answer:

25.0 g.

Explanation:

  • From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.
  • <em>So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.</em>
  • <em>Thus, the grams of the dry salt that will be recovered is 25.0 g.</em>

5 0
3 years ago
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