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Alex
3 years ago
5

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

the visible spectrum. Suppose a particular cone cell absorbs light with a wavelength of 430. nm . Calculate the frequency of this light. Round your answer to 3 significant digits.
Chemistry
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

The frequency of this light is 6.98\times 10^{14} s^{-1}.

Explanation:

Wavelength of the light = \lambda = 430 nm=4.30\times 10^{-7} m

Speed of the light = c = = 3\times 10^8 m/s

Frequency of the light = \nu

\nu =\frac{c}{\lambda }

\nu =\frac{3\times 10^8 m/s}{4.30\times 10^{-7} m}=6.98\times 10^{14} s^{-1}

The frequency of this light is 6.98\times 10^{14} s^{-1}.

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A cylinder with a moveable piston contains 0.552 mol of gas and has a volume of 259 mL . Part A What will its volume be if an ad
Naddik [55]

Answer:

The new volume will be 367mL

Explanation:

Using PV = nRT

V1 = 259mL = 0.000259L

n1 = 0.552moles

At constant temperature and pressure, the value is

P * 0.000259 = 0.552 * RT ------equation 1

= 0.552 / 0.000259

= 2131.274

V2 = ?

n2 = 0.552 + 0.232

n2 = 0.784mole

Using ideal gas equation,

PV = nRT

P * V2 = 0.784 * RT ---------- equation 2

Combining equations 1 and 2 we have;

V2 = 0.784 / 2131.274

V2 = 0.000367L

V2 = 367mL

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3 years ago
How many atoms of chlorine are represented below? 9NaCL
Margaret [11]

Answer:

there are 9 Chlorine atoms

Explanation:

6 0
3 years ago
A solid keeps its shape due to which of the following factors? (3 points)
algol [13]

Answer: Attractive forces between particels

Explanation:

8 0
3 years ago
Alkali metals, alkaline earth metals, and aluminum all form ions with positive charges equal to the
Amiraneli [1.4K]
B. group number is the correct answer

6 0
3 years ago
Read 2 more answers
A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu
OLEGan [10]

Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

    mass of Ni, m = 15.0 g,

   Initial temperature, t_{i} = 100^{o}C,

   Final temperature, t_{f} = ?

 Specific heat of nickel = 0.444 J/g^{o}C

Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

              q_{water}(gain) = -q_{alloy}(lost)

55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

6 0
3 years ago
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