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Liula [17]
3 years ago
7

Where is 0.5 on the graph? I have to do ( 0.5, 4)

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

It would be between the 0 and the 1 on the horizontal line

0.5 is where the blue dot is, then for 0.5 , 4 just go up 4 from there

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I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
I need help with number 1
Marianna [84]

Answer:

1a. 0< -4 false

1b. -3> or = -7 true

1c. 4<= -1/2 false

8 0
3 years ago
Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q
tangare [24]

Answer:

11

Step-by-step explanation:

Hello,

Given the original number n.

\large \boxed{n}

Multiply the number by 9.

\large \boxed{9n}

Add 99.

\large \boxed{9n+99}

Divide this sum by 9.

\large \boxed{\dfrac{9n+99}{9}=n+11}

Subtract the original number, n, from the quotient.

\large \boxed{n+11-n=11}

Thank you.

4 0
3 years ago
I need some help on these questions thanks
GuDViN [60]

Answer:

theres no questions

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
When ms. shreve solved an equation in class, she checked her solution and found that it did not make the equation true! Examine
IgorC [24]
The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
2x=14
x=7
7 0
3 years ago
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