(y-k)²/a² + (x-h)²/b² = 1
Vertices being : A(0,1) & B(0, - 9), means that h=0
Let's calculate k: Af₁ + Af₂ = |2+8| = 2a = 10 → a=5 (f₁ and f₂ = focii)
1) a = 10 (WRONG) since a =5
2) h=3 (WRONG) since h =0
3) k =0 (WRONG) since k =5
4) b = 4 RIGHT; PROOF:
we know that : c² = a² - b²
c= 3 & a = 5 then → 3² = 5² - b²
9 = 25 - b²
b² = 25-9 = 16 and b = 4
Answer:

Step-by-step explanation:
<u>Alternating Sequences</u>
A sequence whose terms alternate in the sign is called an alternating sequence.
The given sequence consists of the numbers -6 and 6 in infinite alternation.
Such sequences can be expressed as equations of the form

Where a is the constant absolute value of each term and m is an expression adequately arranged to reproduce the alternation of signs.
Since the sign is minus for odd terms, and plus for even terms, m=n is a good expression for m. Thus:

Answer:
if u mean absolute value it is 5.
the value is always positive an dmeans how far is it from the numberline
Step-by-step explanation:
Answer:
x + 2y
Step-by-step explanation:
so 3x + 2y - 3x, group the like terms 3x - 3x = x
So x + 2y, i think i did that right