Multiply both sides of the first equation by 3.
Multiply both sides of the second equation by 2.
6x + 9y = 3
-6x - 4y = -2
Now add them.
5x = 1
x = 1/5
Now plug in 1/5 for x in the first original equation.
2x + 3y = 1
2 * 1/5 + 3y = 1
2/5 + 3y = 1
2 + 15y = 5
15y = 3
y = 1/5
The solution is x = 1/5; y = 1/5.
There is one solution.
Answer:
The correct answer is there are 3 cages and 4 tigers.
Step-by-step explanation:
Let there be x cages and y tigers.
According to the first condition, if we put one tiger in each cage, one tiger is left over.
∴ y - x =1
According to the second condition, if we put two tigers in each cage, one cage is left over.
∴ x - 
=1
⇒ 2x - y = 2
Therefore adding both the equations we get,
y - x + 2x - y = 2 + 1
⇒ x = 3
⇒ y = 4
Therefore there are 4 tigers and 3 cages.
190 is the correct answer
Answer:
She made 10 free throws
Step-by-step explination:
I found it on this website: https://staff.4j.lane.edu/~ruzicka/Cal_Young/math/Illustrative%20Math/Unit%203%20Rates%20and%20Percents/Lesson%2011/L11%20HW%20Key%20Corrected.pdf
Try it and see if you are right
X=55 since the triangle is 90*
