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anygoal [31]
3 years ago
5

F(x+1)+f(x+2)=2x+3; f(x)=?

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

Step-by-step explanation:

1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\
F\left(x+1\right)+f\left(x+2\right)-f\left(x+2\right)=2x+3f-f\left(x+2\right)



2. \mathrm{Simplify}\\
F\left(x+1\right)=-xf+f+2x\\


3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\ne \:-1\\
\frac{F\left(x+1\right)}{x+1}=-\frac{xf}{x+1}+\frac{f}{x+1}+\frac{2x}{x+1};\quad \:x\ne \:-1

4. \mathrm{Simplify}\\
F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

Final Answer: F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

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