Another name for the set of all x-values for a relation is: domain.
<h3>What is the Domain of a Relation?</h3>
The domain of a relation can be defined as all the x-values that corresponds to the y-values that are plotted on a graph.
They are referred to as the input or the domain of the relation. Therefore, another name for the set of all x-values plotted for a relation on a graph is: domain.
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<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Answer:
296.89 m
Step-by-step explanation:
assuming that both the buildings are on level ground (i.e their bases are at the same elevation), see attached.
Answer:
mRP = 125°
mQS = 125°
mPQR = 235°
mRPQ = 305°
Step-by-step explanation:
Given that
Then:
- measure of arc RP, mRP = mROP = 125°
Given that
- ∠QOS and ∠ROP are vertical angles
Then:
- measure of arc QS, mQS = mROP = 125°
Given that
- ∠QOR and ∠SOP are vertical angles
Then:
Given that
- The addition of all central angles of a circle is 360°
Then:
mQOS + mROP + mQOR + mSOP = 360°
250° + 2mQOR = 360°
mQOR = (360°- 250°)/2
mQOR = mSOP = 55°
And (QOR and SOP are central angles):
- measure of arc QR, mQR = mQOR = 55°
- measure of arc SP, mSP = mSOP = 55°
Finally:
measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°
measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°
