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3 years ago

6

Is -3.7 less than,greater than or equal to -3.8 ?

1 answer:

Kisachek [45]3 years ago

4 0

-3.7 is greater than -3.8, but is it not less than of equal to -3.8

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Please help me with this

Tamiku [17]

Answer:

20%

hope it helps you

8 0

2 years ago

The Sugar Sweet Company is going to transport its sugar to market. It will cost $4500 to rent trucks, and it will cost an additi

MariettaO [177]

C(s) = 175s + 4500 or y = 175x + 4500

cost of 12 tons of sugar...
C(12) = 175(12) + 4500
C(12) = 2100 + 4500
C(12) = 6600....so 12 tons of sugar will cost u $ 6600

5 0

3 years ago

-x over 6 -1=-13<br><br><br>show work pleaseee

xenn [34]

Answer:

x=-72

Step-by-step explanation:

-x/6-1=-13

add 1 to both sides

-x/6=-12

multiply 6*-12

-72

x=-72 because -72/6=-12

8 0

2 years ago

6x -2x3 + 10x+2x3+7x4 simply

zmey [24]

$(((6x-(2*(x3)))+10x)+(2*(x3)))+7x4 \\ \\ Then \ we \ simplify \ it \ down \ more. \\ \\ (((6x-(2*(x^3)))+10x)+2x^3)+7x^4 \\ \\ then \ we \ would \ then \ pull \ out \ the \ like \ factors . . . . \\ \\ 7x^4 + 16x = x * (7x^3 + 16) \\ \\$

Your final answer: $\boxed{\bf{ x *(7x^3 + 16)}}$

4 0

2 years ago

Read 2 more answers

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago