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Nesterboy [21]
3 years ago
14

Pat’s softball team won 5 games for every 3 games they lost.

Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

Step-by-step explanation:

5 games won to every 3 games lost...ratio of 5:3....added = 8

so 5/8 of the total games were won and 3/8 of the total games were lost

so if the total games is 32...

they won : 5/8 * 32 = 160/8 = 20 games <==

Vera_Pavlovna [14]3 years ago
6 0

Answer:

20 games were won and 12 games were lost.

Step-by-step explanation:

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Ksenya-84 [330]

Answer:

Solutions:-5,0,9,6

Not solutions: 12.5,10

Explanation:

The inequality that was given is:

20 > 5 + 3x

First, group similar terms;

20 - 5 < 3x

15 < 3x

x = 5

Thus, the solutions are:-3.5, 5, 4 3/4, -15

The not solutions are:-10 2/3, 129,

Hope this helps! :)

7 0
3 years ago
Identify an appropriate method to solve the equation x²- 14 x+ 48= -10
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3 0
3 years ago
Sandra's cell phone plan gives her unlimited minutes for $15.50 per month. She is charged $0.08 for each text message, t. Which
brilliants [131]

Answer:

c=15.50+0.08t

Step-by-step explanation:

3 0
3 years ago
Use DeMoivre's Theorem to find (3cis*pi/6)^3
Sonbull [250]

The correct value of (3cis(pi/6))³ is 27i.

<h3>What is Complex Number?</h3>

Complex numbers are numbers that consist of two parts — a real number and an imaginary number. Complex numbers are the building blocks of more intricate math, such as algebra.

Given the complex number in polar coordinate expressed as

z = r(cos∅+isin∅)

zⁿ =  {r(cos∅+isin∅)}ⁿ

According to DeMoivre’s Theorem;

zⁿ =  rⁿ(cosn∅+isinn∅)

Given the complex number;

(3cis(pi/6))³

= {3(cosπ/6 + isinπ/6)}³

Using  DeMoivre’s Theorem;

= 3³(cos3π/6 + isin3π/6)

=  3³(cosπ/2 + isinπ/2)

= 3³(0 + i(1))

= 27i

Thus, the correct value of (3cis(pi/6))³ is 27i.

Learn more about Complex number from:

brainly.com/question/10251853

#SPJ1

7 0
2 years ago
Put these four fractions in order from smallest to largest: 1/4, 2/3, 4/7, 1/2
Alex Ar [27]
1/4, 1/2, 4/7, and 2/3. I hope this helps!
4 0
3 years ago
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