A die used in a certain board game has eight faces, of which 3 are red, 3 are yellow, and 2 are blue. Each face is equally likel
y to land faceup when the die is tossed. In the game, a player tosses the die until blue lands faceup, and the number of tosses before blue lands faceup is counted. For example, a player who tosses the sequence shown in the following table has tossed the die 3 times before blue lands faceup. What is the probability that a player will toss the die at least 2 times before blue lands faceup? A 0.1406 B 0.4219 C 0.4375 D 0.5625 E 0.5781
5/7-4/6 take the least common multiple of six and seven which is 42 5*whatever multiple of 7 that gives you 42 5*6=30 plus 4* whatever multiple of six that gives you 42 4*7=28 subtract 28 from 42 your answer 14