What is 24% of 80 plzz help

Plssssss help me pls no fake answers and pls no links and pls answer both questions

lozanna [386]

false for 4.

ture for the 1st one

brianliest me

4 0

2 years ago

Read 2 more answers

-8+y=14

Sati [7]

Answer:

y = 22

Step-by-step explanation:

we want to move the -8 to the other side, so 14+8 = 22

y = 22

check: -8 + 22 = 14

8 0

3 years ago

Read 2 more answers

Find 5x − 3y − z if x = −2, y = 2, and z = −3 <br> Select one: a. −19 b. 19 c. 13 d. −13

NeTakaya

Answer:

-13

Step-by-step explanation:

5x − 3y − z

substitute x = −2, y = 2, and z = −3

5(-2) -3(2) - (-3)

multiply

-10 -6 +3

-16 +3

-13

7 0

3 years ago

Label the place value 9 is in 7854.209

iVinArrow [24]

Thousandth ( Tth )
The reason is just because of the place value laws.

6 0

3 years ago

Select the point that is a solution to the system of inequalities

Zarrin [17]

<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

$y\leq 2x-2$

$y\leq x^{2} -3x$

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$1\leq (2)^{2} -3(2)$

$1\leq 4 -6$

$1\leq -2$

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$-1\leq (-2)^{2} -3(-2)$

$-1\leq 4 +6$

$-1\leq 10$

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$2\leq (4)^{2} -3(4)$

$2\leq 16 -12$

$2\leq 4$

Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$3\leq (1)^{2} -3(1)$

$3\leq 1 -3$

$3\leq -2$

Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.

Hence, the point that is a solution to the system of inequalities is C(4,2).

Have a nice day!

6 0

3 years ago